The atomic mass of 6C12 is 12.000000 u and that of 6C13 is 13.003354 u. The required energy to remove a neutron from 6C13, if mass of neutron is 1.008665 u, will be :
- 62.5 MeV
- 6.25 MeV
- 4.95 MeV
- 49.5 MeV
Answer
(3) 4.95 MeV
Solution
6C13+E 6C12+0n1
m=(12.000000+1.008665)-13.003354
=0.005311 u
E=0.005311 931.5 MeV 4.95 MeV
Answer: (3)