X is the number of geometrical isomers exhibited by [Pt(NH3)(H2O)BrCl]. Y is the number of optically inactive isomer(s) exhibited by [CrCl2(ox)2]3-. Z is the number of geometrical isomers exhibited by [Co(NH3)3(NO2)3]. The value of X + Y + Z is .
Answer
6
Solution
X: [Pt(NH3)(H2O)BrCl] is square planar of type [Mabcd]
3 geometrical isomers (fix a; b, c or d can be trans to it) X = 3
Y: [CrCl2(ox)2]3- is octahedral of type [M(AA)2b2]
cis-isomer: no plane of symmetry optically active (d and l pair)
trans-isomer: has a plane of symmetry optically inactive
Y = 1
Z: [Co(NH3)3(NO2)3] is octahedral of type [Ma3b3]
fac and mer isomers Z = 2
X + Y + Z = 3 + 1 + 2 = 6
Answer: 6