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Integrals · Question 51

JEE Main 2025 (Online) 28th January Evening ShiftMCQMedium📈 Topic in 6% papers+4−1
1

Let f be a real valued continuous function defined on the positive real axis such that g(x) = 0x t f(t) dt. If g (x3 ) = x6 + x7, then value of r=115 f (r3 ) is :

  1. 270
  2. 340
  3. 310
  4. 320

Answer

(3) 310

Solution

g(x) = 0x t f(t) dt g'(x) = x f(x)

Differentiating g(x3) = x6 + x7:

g'(x3) 3x2 = 6x5 + 7x6

x3 f(x3) 3x2 = 6x5 + 7x6

f(x3) = 6x5 + 7x63x5 = 2 + 7x3

r=115 f(r3) = r=115 (2 + 7r3 )

= 30 + 73 15 162

= 30 + 73 120 = 30 + 280 = 310

Answer: (3)

JEE Main 2025 (Online) 28th January Evening Shift

Keep practising — Integrals

2

The value of the integral 02 x (x2+x+1 ) ( x+1 ) ( x4+x2+1 ) dx is equal to :

  1. 13 e (3-2 2 )
  2. 23 e (4+ 2 )
  3. 23 e (3+2 2 )
  4. 13 e (1+6 2 )
JEE Main 2026 (Online) 8th April Evening Shift
3

If /6 /4 ( (x- 3 ) (x+ 3 )+1 )dx = e ( 3-1 ), then 9 2 is equal to .

JEE Main 2026 (Online) 8th April Evening Shift
4

The value of the integral - /4 /4 ( 32 4 x1+e x )dx is :

  1. 4 +2
  2. 3 +8
  3. 3 +4
  4. 4 +3
JEE Main 2026 (Online) 6th April Morning Shift
5

The value of the integral -11 ( x3+|x|+1x2+2|x|+1 )dx is equal to :

  1. 3 e 2
  2. 2 e 2
  3. 5 e 3
  4. 3 e 3
JEE Main 2026 (Online) 6th April Evening Shift
6

The value of the integral 0 e(x)x2+4 dx is:

  1. e(2)2
  2. e(2)4
  3. 1+ e(2)
  4. 2+ e(2)
JEE Main 2026 (Online) 5th April Morning Shift
7

The value of the integral 6 3 ( 4-cosec2 x 4 x )dx is :

  1. 11 3
  2. 16 3
  3. 323 3
  4. 643 3
JEE Main 2026 (Online) 5th April Morning Shift
8

Let (21-a+21+a ), f(a), (3a+3-a ) be in A.P. and be the minimum value of f(a). Then the value of the integral e( -1) e( ) dx (e2x-e-2x ) is :

  1. 12 e ( 43 )
  2. 14 e ( 43 )
  3. 12 e ( 85 )
  4. 14 e ( 85 )
JEE Main 2026 (Online) 5th April Evening Shift
9

Let f : [1, ) R be a differentiable function defined as f(x)= 1x f(t) dt +(1-x) ( e x-1 )+e. Then the value of f(f(1)) is :

  1. (1+ee )
  2. (1+e)
  3. (1+e+ee )
  4. 1+2e
JEE Main 2026 (Online) 5th April Evening Shift
10

Let -22 (| x|+[x x] )dx=2(3- 2)+ , where [ ] is the greatest integer function. Then ( 2 ) equals:

  1. 1
  2. 2
  3. 4
  4. 8
JEE Main 2026 (Online) 4th April Morning Shift
11

If =1 and =1+i 2, where i= -1 are two roots of the equation x3+ax2+bx+c=0, a, b, c R, then -11 (x3+ax2+bx+c )dx is equal to :

  1. -2
  2. -4
  3. -8
  4. -10
JEE Main 2026 (Online) 4th April Evening Shift

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