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Wave Optics · Question 36

NEET 2013 (Karnataka)MCQEasy📈 Topic in 0% papers+4−1
1

A parallel beam of light of wavelength is incident normally on a narrow slit. A diffraction pattern is formed on a screen placed perpendicular to the direction of the incident beam. At the second minimum of the diffraction pattern, the phase difference between the rays coming from the two edges of slit is

  1. 2
  2. 3
  3. 4

Answer

(3) 4

Solution

For the nth minimum of single-slit diffraction: a = n

Second minimum (n = 2): path difference between the edge rays = 2

Phase difference = 2 2 = 4

Answer: (3)

NEET 2013 (Karnataka)

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2

The angular resolution of a 10 cm diameter telescope at a wavelength of 5000 A is of the order of

  1. 106 rad
  2. 10-2 rad
  3. 10-4 rad
  4. 10-6 rad.
AIPMT 2005
3

A telescope has an objective lens of 10 cm diameter and is situated at a distance of one kilometer from two objects. The minimum distance between these two objects, which can be resolved by the telescope, when the mean wavelength of light is 5000 A, is of the order of

  1. 0.5 m
  2. 5 m
  3. 5 mm
  4. 5 cm
AIPMT 2004
4

Diameter of human eye lens is 2 mm. What will be the minimum distance between two points to resolve them, which are situated at a distance of 50 metre from the eye? The wavelength of light is 5000 Å.

  1. 2.32 m
  2. 4.28 mm
  3. 1.25 cm
  4. 12.48 cm
AIPMT 2002

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