Let chord PQ of length 3 13 of the parabola y2=12x be such that the ordinates of points P and Q are in the ratio 1 : 2. If the chord PQ subtends an angle at the focus of the parabola, then is equal to :
- 35
- 45
- 513
- 1213
Answer
(1) 35
Solution
[figure]
y2=12x 4a=12, a=3; focus S(3, 0); any point (3t2, 6t )
Ordinates in the ratio 1 : 2 P (3t2, 6t ), Q (12t2, 12t )
PQ2= (9t2 )2+(6t)2=81t4+36t2
PQ=3 13 81t4+36t2=117
9t4+4t2-13=0 (t2-1 ) (9t2+13 )=0 t2=1
Take t=1 (t=-1 gives the mirror image in the x-axis, same angle) : P(3, 6), Q(12, 12)
SP=(0, 6), | SP|=6; SQ=(9, 12), | SQ|=15
= 0 9+6 126 15= 7290= 45
= 1- 1625= 35
Answer: (1)