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Let the coefficient of xr in the expansion of (x+3)n-1+(x+3)n-2(x+2)+(x+3)n-3(x+2)2+ +(x+2)n-1 be r. If r=0n r= n- n, , N, then the value of 2+ 2 equals .
25
Sum of all coefficients = value at x=1:
r=4n-1+4n-2 3+4n-3 32+ +3n-1
∵ G.P. with ratio qp: pn-1+pn-2q+ +qn-1= pn-qnp-q
r= 4n-3n4-3=4n-3n =4, =3
2+ 2=16+9=25
Answer: 25
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