Moment of inertia of a rod of mass 'M' and length 'L' about an axis passing through its center and normal to its length is ' '. Now the rod is cut into two equal parts and these parts are joined symmetrically to form a cross shape. Moment of inertia of cross about an axis passing through its center and normal to plane containing cross is :
- /4
- /8
- /2
Answer
(1) /4
Solution
= ML212
Each part: mass M2, length L2; in the cross the centre of each part is at the common centre.
MI of one part about the axis = 112 ( M2 ) ( L2 )2 = ML296
Icross = 2 ML296 = ML248 = 14 ML212 = 4
Answer: (1)