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System of Particles and Rotational Motion · Question 42

JEE Main 2025 (Online) 2nd April Morning ShiftMCQEasy📈 Topic in 23% papers+4−1
1

Moment of inertia of a rod of mass 'M' and length 'L' about an axis passing through its center and normal to its length is ' '. Now the rod is cut into two equal parts and these parts are joined symmetrically to form a cross shape. Moment of inertia of cross about an axis passing through its center and normal to plane containing cross is :

  1. /4
  2. /8
  3. /2

Answer

(1) /4

Solution

= ML212

Each part: mass M2, length L2; in the cross the centre of each part is at the common centre.

MI of one part about the axis = 112 ( M2 ) ( L2 )2 = ML296

Icross = 2 ML296 = ML248 = 14 ML212 = 4

Answer: (1)

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2

A square lamina OABC of length 10 cm is pivoted at 'O'. Forces act at lamina as shown in figure. If lamina remains stationary, then the magnitude of F is : [figure]

  1. 10 N
  2. 0 (zero)
  3. 10 2 N
  4. 20 N
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3

A cord of negligible mass is wound around the rim of a wheel supported by spokes with negligible mass. The mass of wheel is 10 kg and radius is 10 cm and it can freely rotate without any friction. Initially the wheel is at rest. If a steady pull of 20 N is applied on the cord, the angular velocity of the wheel, after the cord is unwound by 1 m, would be: [figure]

  1. 20 rad/s
  2. 30 rad/s
  3. 10 rad/s
  4. 0 rad/s
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4

The moment of inertia of a circular ring of mass M and diameter r about a tangential axis lying in the plane of the ring is :

  1. 38Mr2
  2. 2Mr2
  3. 12Mr2
  4. 32Mr2
JEE Main 2025 (Online) 2nd April Evening Shift
5

[figure] A wheel of radius 0.2 m rotates freely about its center when a string that is wrapped over its rim is pulled by a force of 10 N as shown in figure. The established torque produces an angular acceleration of 2 rad/s2. Moment of inertia of the wheel is kg m2. (Acceleration due to gravity = 10 m/s2)

JEE Main 2025 (Online) 2nd April Evening Shift
6

The coordinates of a particle with respect to origin in a given reference frame is (1, 1, 1) meters. If a force of F = i - j + k acts on the particle, then the magnitude of torque (with respect to origin) in z-direction is .

JEE Main 2025 (Online) 29th January Morning Shift
7

The center of mass of a thin rectangular plate (fig - x) with sides of length a and b, whose mass per unit area ( ) varies as = 0 xab (where 0 is a constant), would be . [figure]

  1. ( 23a, 23b )
  2. ( 23a, b2 )
  3. ( 13a, b2 )
  4. ( a2, b2 )
JEE Main 2025 (Online) 28th January Morning Shift
8

Two iron solid discs of negligible thickness have radii R1 and R2 and moment of inertia I1 and I2, respectively. For R2 = 2R1, the ratio of I1 and I2 would be 1/x, where x = .

JEE Main 2025 (Online) 28th January Morning Shift
9

The moment of inertia of a solid disc rotating along its diameter is 2.5 times higher than the moment of inertia of a ring rotating in similar way. The moment of inertia of a solid sphere which has same radius as the disc and rotating in similar way, is n times higher than the moment of inertia of the given ring. Here, n = . Consider all the bodies have equal masses.

JEE Main 2025 (Online) 28th January Morning Shift
10

A uniform rod of mass 250 g having length 100 cm is balanced on a sharp edge at 40 cm mark. A mass of 400 g is suspended at 10 cm mark. To maintain the balance of the rod, the mass to be suspended at 90 cm mark, is

  1. 290 g
  2. 200 g
  3. 190 g
  4. 300 g
JEE Main 2025 (Online) 28th January Evening Shift

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