A body of weight 200 N is suspended from a tree branch through a chain of mass 10 kg. The branch pulls the chain by a force equal to (if g = 10 m/s2) :
- 300 N
- 100 N
- 150 N
- 200 N
Answer
(1) 300 N
Solution
FBD of (chain + body) taken as one system at rest:
[figure]
Weight of chain = 10 10 = 100 N
the system is in equilibrium: T = 200 + 100
T = 300 N
Answer: (1)