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Two slits are 1 mm apart and the screen is located 1 m away from the slits. A light of wavelength 500 nm is used. The width of each slit to obtain 10 maxima of the double slit pattern within the central maximum of the single slit pattern is 10-4 m.
2
Width of central maximum (single slit) = 2 Da; fringe width = Dd
10 maxima fit in the central maximum:
2 Da = 10 Dd
a = d5 = 1 10-35 = 2 10-4 m
Answer: 2
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