A microwave of wavelength 2.0 cm falls normally on a slit of width 4.0 cm. The angular spread of the central maxima of the diffraction pattern obtained on a screen 1.5 m away from the slit, will be :
- 60
- 45
- 15
- 30
Answer
(1) 60
Solution
First minimum: a =
= 2.04.0= 12 =30
the central maximum spreads from - to +
angular spread =2 =60 (screen distance not needed)
Answer: (1)