A uniform wire of length l of weight w is suspended from the roof with a weight of W at the other end. The stress in the wire at l3 distance from the top is ( WA+ 2 wA ), where A is the cross sectional area of the wire. The value of is .
Answer
3
Solution
The section at l3 from the top has a length l- l3= 2l3 of wire below it.
Weight of that part = 23w (uniform wire)
Tension there: T=W+ 23w
Stress = TA= WA+ 23 wA
Comparing with WA+ 2 wA: =3
Answer: 3