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Thermodynamics

JEE Main 2025 (Online) 22nd January Evening ShiftMatchingEasy📈 Topic in 29% papers+4−1
Ques. 1JEE Main 2025, 22 January (Evening Shift)

Match List - I with List - II. Choose the correct answer from the options given below :

  1. A-I, B-II, C-IV, D-III
  2. A-II, B-III, C-I, D-IV
  3. A-II, B-I, C-IV, D-III
  4. A-II, B-I, C-III, D-IV

Answer

(3) A-II, B-I, C-IV, D-III

Solution

dG=-S dT+V dP ⇒ ( G T )P=-S (II), ( G P )T=V (IV)

Cp= ( H T )P (I), Cv= ( U T )V (III)

∴ A-II, B-I, C-IV, D-III

Answer: (3)

Keep practising — Thermodynamics

Ques. 2JEE Main 2025, 22 January (Evening Shift)

Consider the following cases of standard enthalpy of reaction ( Hr in kJ mol-1) C2H6(g)+ 72O2(g) 2CO2(g)+3H2O(l) H1 =-1550 C(graphite)+O2(g) CO2(g) H2 =-393.5 H2(g)+ 12O2(g) H2O(l) H3 =-286 The magnitude of H f C2H6(g) is kJ mol-1 (Nearest integer).

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