Ques. 1JEE Main 2024, 8 April (Morning Shift)
Let P(x, y, z) be a point in the first octant, whose projection in the xy-plane is the point Q. Let OP = ; the angle between OQ and the positive x-axis be ; and the angle between OP and the positive z-axis be , where O is the origin. Then the distance of P from the x-axis is
- 1 - 2 2
- 1 + 2 2
- 1 + 2 2
- 1 - 2 2
Answer
(1) 1 - 2 2
Solution
[figure]
(right angle at Q): z = QP = , OQ =
In the xy-plane: x = OQ =
Distance of P from x-axis = y2 + z2 = 2 - x2
= 1 - 2 2
Answer: (1)