An electron is moving in a circular path under the influence of a transverse magnetic field of 3.57 10-2 T. If the value of e/m is 1.76 1011 C kg-1, the frequency of revolution of the electron is
- 1 GHz
- 100 MHz
- 62.8 MHz
- 6.28 MHz
Answer
(1) 1 GHz
Solution
Frequency of revolution (cyclotron frequency): = eB2 m
= 1.76 1011 3.57 10-22 3.14
= 6.28 1096.28
= 109 Hz = 1 GHz
Answer: (1)