Two identical long conducting wires AOB and COD are placed at right angle to each other, with one above other such that O is their common point for the two. The wires carry I1 and I2 currents, respectively. Point P is lying at distance d from O along a direction perpendicular to the plane containing the wires. The magnetic field at the point P will be
- 02 d ( I1I2 )
- 02 d (I1 + I2 )
- 02 d (I12 - I22 )
- 02 d (I12 + I22 )1/2
Answer
(4) 02 d (I12 + I22 )1/2
Solution
Field at P due to each long wire (P is at perpendicular distance d from both):
B1 = 0 I12 d, B2 = 0 I22 d
The wires are perpendicular to each other, B1 and B2 are also perpendicular to each other.
B = B12 + B22
= 02 d (I12 + I22 )1/2
Answer: (4)