An equiconvex lens is cut into two halves along (i) XOX′ and (ii) YOY′ as shown in the figure. Let f, f', f'' be the focal lengths of the complete lens, of each half in case (i), and of each half in case (ii), respectively. Choose the correct statement from the following [figure]
- f' = f, f'' = 2f
- f' = 2f, f'' = f
- f' = f, f'' = f
- f' = 2f, f'' = 2f
Answer
(1) f' = f, f'' = 2f
Solution
For the equiconvex lens (radii R and −R), by the lens maker's formula:
1f = ( - 1) ( 1R + 1R ) = 2( - 1)R
Case (i): cut along XOX′ (the principal axis). Each half still has both curved surfaces of radius R.
⇒ 1f' = 2( - 1)R ⇒ f' = f (only the amount of light, i.e. intensity, is halved)
Case (ii): cut along YOY′ (perpendicular to the axis). Each half is plano-convex (R2 = ).
⇒ 1f'' = ( - 1) ( 1R - 1 ) = - 1R
⇒ f'' = 2f
Answer: (1)