The major product of the following reaction is P. CH3C C - CH3 [ (ii) dil. KMnO4 \ 273 K](i) Na/liq. NH3 'P' Number of oxygen atoms present in product 'P' is . (nearest integer)
Answer
2
Solution
CH3C CCH3 Na/liq. NH3 CH3CH=CHCH3
[273 K]dil. KMnO4 CH3- OH |CH- OH |CH-CH3 (P)
∵ Na/liq. NH3 (anti addition of H) gives trans-but-2-ene; cold dil. KMnO4 adds two –OH (syn) ⇒ P = butane-2,3-diol
∴ oxygen atoms in P = 2
Answer: 2