When a long spring is stretched by 2 cm, its potential energy is U. If the spring is stretched by 10 cm, the potential energy stored in it will be
- U/5
- 5U
- 10U
- 25U
Answer
(4) 25U
Solution
Potential energy of a spring: U = 12kx2 ⇒ U x2
⇒ U'U = ( 102 )2
= 25
∴ U' = 25U
Answer: (4)