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Sets · Question 3

JEE Main 2025 (Online) 7th April Evening ShiftMCQEasy📈 Topic in 6% papers+4−1
1

Let A = \( , ) R R : | - 1| 4 and | - 5| 6\ and B = \( , ) R R : 16( - 2)2 + 9( - 6)2 144\. Then

  1. A B
  2. B A
  3. neither A B nor B A
  4. A B = \(x, y) : -4 x 4, -1 y 11\

Answer

(2) B A

Solution

Set A: | - 1| 4 -3 5 and | - 5| 6 -1 11.

So A is the rectangle [-3, 5] [-1, 11].

Set B: 16( - 2)2 + 9( - 6)2 144 ( - 2)29 + ( - 6)216 1

This is the region inside the ellipse with centre (2, 6), semi-axes 3 (along ) and 4 (along ).

every point of B has -1 5 and 2 10

[-1, 5] [-3, 5] and [2, 10] [-1, 11], every point of B lies in A.

B A (A is not a subset of B, e.g. (-3, -1) A but B).

Also A B = A = \(x, y) : -3 x 5, -1 y 11\, so option (4) is false.

Answer: (2)

JEE Main 2025 (Online) 7th April Evening Shift

Keep practising — Sets

2

Let A = \1, 6, 11, 16, \ and B = \9, 16, 23, 30, \ be the sets consisting of the first 2025 terms of two arithmetic progressions. Then n(A B) is

  1. 3814
  2. 4003
  3. 4027
  4. 3761
JEE Main 2025 (Online) 4th April Morning Shift

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