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Permutations and Combinations · Question 32

JEE Main 2025 (Online) 29th January Morning ShiftNumericalMedium📈 Topic in 23% papers+4
1

The number of 6-letter words, with or without meaning, that can be formed using the letters of the word MATHS such that any letter that appears in the word must appear at least twice, is .

Answer

1405

Solution

MATHS has 5 distinct letters. Each letter used must occur at least twice, so the multiplicities form a partition of 6 into parts 2.

(i) 6 : one letter six times 5 1 = 5

(ii) 4 + 2 : 5 4 6!4! 2! = 20 15 = 300

(iii) 3 + 3 : 5C2 6!3! 3! = 10 20 = 200

(iv) 2 + 2 + 2 : 5C3 6!2! 2! 2! = 10 90 = 900

total = 5 + 300 + 200 + 900 = 1405

Answer: 1405

JEE Main 2025 (Online) 29th January Morning Shift

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2

Let nCr-1 = 28, nCr = 56 and nCr+1 = 70. Let A(4 t, 4 t), B(2 t, -2 t) and C (3r - n, r2 - n - 1 ) be the vertices of a triangle ABC, where t is a parameter. If (3x - 1)2 + (3y)2 = , is the locus of the centroid of triangle ABC, then equals

  1. 18
  2. 8
  3. 20
  4. 6
JEE Main 2025 (Online) 28th January Morning Shift
3

The number of different 5 digit numbers greater than 50000 that can be formed using the digits 0, 1, 2, 3, 4, 5, 6, 7, such that the sum of their first and last digits should not be more than 8, is

  1. 5720
  2. 5719
  3. 4608
  4. 4607
JEE Main 2025 (Online) 28th January Morning Shift
4

The number of natural numbers, between 212 and 999, such that the sum of their digits is 15, is .

JEE Main 2025 (Online) 28th January Evening Shift

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