1
Let the function f: R R be defined by f(x)= xe x (x2023+2024x+2025 ) (x2-x+3 )+ 2e x (x2023+2024x+2025 ) (x2-x+3 ). Then the number of solutions of f(x)=0 in R is .
JEE Advanced 2024 Paper 2
Application of Derivatives
Previous year questions with solutions · 2024 – 2026
5Questions
4Papers covered
2.94% ↓68.6%Weightage in 2026
’24
’25
’26
Year-wise statistics questions · papers · average per paper · weightage
| Year | Questions | Papers | Avg / paper | Weightage |
|---|---|---|---|---|
| 2026 | 1 | 2 | 0.5 | 2.94% ↓68.6% |
| 2025 | 3 | 2 | 1.5 | 9.38% ↑218.7% |
| 2024 | 1 | 2 | 0.5 | 2.94% |