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Differential Equations

Previous year questions with solutions · 2024 – 2026

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5Questions
4Papers covered
5.88% ↓5.9%Weightage in 2026
’24
’25
’26
Year-wise statistics questions · papers · average per paper · weightage
YearQuestionsPapersAvg / paperWeightage
20262215.88% ↓5.9%
20252216.25% ↑112.5%
2024120.52.94%

2 questions · newest paper first

1

Let y:(- , ) (0, ) be the solution of the differential equation dydx= e5xy3+y3ex+exy4, satisfying y(0)= 1 2. Then the value of y( e 2) is

  1. 5+ 352
  2. 7+ 532
  3. 7+ 532
  4. 5+ 352
JEE Advanced 2026 Paper 2
2

For all x > 0, let y1(x), y2(x), and y3(x) be the functions satisfying dy1dx - ( x)2y1 = 0, y1(1) = 5, dy2dx - ( x)2y2 = 0, y2(1) = 13, dy3dx - ( 2 - x3x3 )y3 = 0, y3(1) = 35e, respectively. Then x 0+ y1(x)y2(x)y3(x) + 2xe3x x is equal to .

JEE Advanced 2025 Paper 1