Let y:(- , ) (0, ) be the solution of the differential equation dydx= e5xy3+y3ex+exy4, satisfying y(0)= 1 2. Then the value of y( e 2) is
- 5+ 352
- 7+ 532
- 7+ 532
- 5+ 352
Answer
(2) 7+ 532
Solution
Variables separable: dydx= y3(e5x+1)ex(1+y4).
(y-3+y )dy= (e4x+e-x )dx - 12y2+ y22= e4x4-e-x+C.
At x=0, y2= 12: -1+ 14= 14-1+C C=0.
At x= e 2: RHS = 164- 12= 72. Put u=y2: u- 1u=7 u2-7u-1=0 u= 7+ 532 (u>0).
y( e 2)= 7+ 532.
Answer: (B)