Differential Equations

For all x > 0, let y1(x), y2(x), and y3(x) be the functions satisfying dy1dx - ( x)2y1 = 0, y1(1) = 5, dy2dx - ( x)2y2 = 0, y2(1) = 13, dy3dx - ( 2 - x3x3 )y3 = 0, y3(1) = 35e, respectively. Then x 0+ y1(x)y2(x)y3(x) + 2xe3x x is equal to .

Let y(x) be the solution of the differential equation x2 dydx+xy=x2+y2, x> 1e, satisfying y(1)=0. Then the value of 2 (y(e))2y(e2) is .