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The value of the definite integral 02 13x+3 dx is
(2) 13
Use 0af(x) dx= 0af(a-x) dx with a=2.
f(2-x)= 132-x+3= 3x9+3 3x= 3x3(3x+3).
f(x)+f(2-x)= 3+3x3(3x+3)= 13.
2I= 02 13 dx= 23 I= 13.
Answer: (B)
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