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If x 0 ( xx ) 1x2 = p, then 96 e p is equal to
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Previous year questions with solutions · 2025 – 2026
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|---|---|---|---|---|
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| 2025 | 9 | 12 | 0.75 | 3.00% |
If x 0 ( xx ) 1x2 = p, then 96 e p is equal to
Let [t] be the greatest integer less than or equal to t. Then the least value of p N for which x 0+ (x ( [ 1x ] + [ 2x ] + + [ px ] ) - x2 ( [ 1x2 ] + [ 22x2 ] + + [ 92x2 ] ) ) 1 is equal to .
Let f(x) = n r=0n ( (x/2r+1 ) + 3 (x/2r+1 )1 - 2 (x/2r+1 ) ). Then x 0 ex - ef(x)(x - f(x)) is equal to .