1
The sum of squares of all the real solutions of the equation (x+1) (2x2+5x+3 )=4- (2x+3) (x2+2x+1 ) is equal to .
JEE Main 2026 (Online) 8th April Evening Shift
Relations and Functions
Previous year questions with solutions · 2025 – 2026
19Questions
16Papers covered
2.32% ↓13.2%Weightage in 2026
’25
’26
Year-wise statistics questions · papers · average per paper · weightage
| Year | Questions | Papers | Avg / paper | Weightage |
|---|---|---|---|---|
| 2026 | 11 | 19 | 0.58 | 2.32% ↓13.2% |
| 2025 | 8 | 12 | 0.67 | 2.67% |
2
Let A=\1, 4, 7\ and B=\2, 3, 8\. Then the number of elements, in the relation R=\((a1, b1), (a2, b2)) ((A B) (A B)) : a1+b2 divides a2+b1\ is .
JEE Main 2026 (Online) 5th April Evening Shift
3
If the domain of the function f(x)= (0.6) ( | 2x-5x2-4 | ) is (- , a] \b\ [c, d) (e, ), then the value of a+b+c+d+e is .
JEE Main 2026 (Online) 2nd April Morning Shift
4
Let A=\2, 3, 4, 5, 6\. Let R be a relation on the set A A given by (x, y)R(z, w) if and only if x divides z and y w. Then the number of elements in R is .
JEE Main 2026 (Online) 2nd April Evening Shift
5
Let the domain of the function f(x) = -1 ( 4x + 53x - 7 ) be [ , ] and the domain of g(x) = 2 (2 - 6 27(2x + 5) ) be ( , ). Then |7( + ) + 4( + )| is equal to .
JEE Main 2025 (Online) 8th April Evening Shift