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Electromagnetic Induction

Previous year questions with solutions · 2025 – 2026

25Questions
16Papers covered
4% ↑100%Weightage in 2026
’25
’26
Year-wise statistics questions · papers · average per paper · weightage
YearQuestionsPapersAvg / paperWeightage
2026191914.00% ↑100%
20256120.52.00%

8 questions · newest paper first

1

A metal rod of length L rotates about one end at origin with a uniform angular velocity . The magnetic field radially falls off as B(r)=B0e- r; being a positive constant. The emf induced (neglecting the centripetal force on electrons in the rod) is :

  1. B0 [ 1 2-e- L ( 1 2+ L ) ]
  2. B0 [ 1 2+e- L ( 1 2+ L ) ]
  3. B0 [ 4 2-e-2 L ( 1 2+ 2L ) ]
  4. B0 [ 3 2-e-3 L ( 3 2+ L ) ]
JEE Main 2026 (Online) 5th April Evening Shift
2

A 20 m long uniform copper wire held horizontally is allowed to fall under the gravity (g = 10 m/s2) through a uniform horizontal magnetic field of 0.5 Gauss perpendicular to the length of the wire. The induced EMF across the wire when it travels a vertical distance of 200 m is mV.

  1. 200 10
  2. 0.2 10
  3. 20 10
  4. 2 10
JEE Main 2026 (Online) 23rd January Morning Shift
3

A simple pendulum made of mass 10 g and a metallic wire of length 10 cm is suspended vertically in a uniform magnetic field of 2 T. The magnetic field direction is perpendicular to the plane of oscillations of the pendulum. If the pendulum is released from an angle of 60 with vertical, then maximum induced EMF between the point of suspension and point of oscillation is mV. (Take g = 10 m/s2)

JEE Main 2026 (Online) 23rd January Morning Shift
4

XPQY is a vertical smooth long loop having a total resistance R where PX is parallel to QY and separation between them is l. A constant magnetic field B perpendicular to the plane of the loop exists in the entire space. A rod CD of length L(L > l) and mass m is made to slide down from rest under the gravity as shown in figure. The terminal speed acquired by the rod is m/s. (g = acceleration due to gravity) [figure]

  1. mgRB2l2
  2. 2mgRB2L2
  3. 2mgRB2l2
  4. 8mgRB2l2
JEE Main 2026 (Online) 22nd January Morning Shift
5

A 1 m long metal rod AB completes the circuit as shown in figure. The area of circuit is perpendicular to the magnetic field of 0.10 T. If the resistance of the total circuit is 2 then the force needed to move the rod towards right with constant speed (v) of 1.5 m/s is N. [figure]

  1. 5.7 10-2
  2. 7.5 10-3
  3. 5.7 10-3
  4. 7.5 10-2
JEE Main 2026 (Online) 21st January Morning Shift
6

Conductor wire ABCDE with each arm 10 cm in length is placed in magnetic field of 1 2 Tesla, perpendicular to its plane. When conductor is pulled towards right with constant velocity of 10 cm/s, induced emf between points A and E is mV. [figure]

JEE Main 2025 (Online) 4th April Morning Shift
7

A uniform magnetic field of 0.4 T acts perpendicular to a circular copper disc 20 cm in radius. The disc is having a uniform angular velocity of 10 rad s-1 about an axis through its centre and perpendicular to the disc. What is the potential difference developed between the axis of the disc and the rim? ( = 3.14)

  1. 0.5024 V
  2. 0.0628 V
  3. 0.2512 V
  4. 0.1256 V
JEE Main 2025 (Online) 28th January Evening Shift
8

[figure] A conducting bar moves on two conducting rails as shown in the figure. A constant magnetic field B exists into the page. The bar starts to move from the vertex at time t = 0 with a constant velocity. If the induced EMF is E tn, then value of n is .

JEE Main 2025 (Online) 28th January Evening Shift