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Electromagnetic Induction · Question 9

JEE Main 2026 (Online) 23rd January Morning ShiftMCQEasy📈 Topic in 19% papers+4−1
1

A 20 m long uniform copper wire held horizontally is allowed to fall under the gravity (g = 10 m/s2) through a uniform horizontal magnetic field of 0.5 Gauss perpendicular to the length of the wire. The induced EMF across the wire when it travels a vertical distance of 200 m is mV.

  1. 200 10
  2. 0.2 10
  3. 20 10
  4. 2 10

Answer

(3) 20 10

Solution

Speed after falling 200 m: v = 2gh = 2 10 200 = 20 10 m/s

B = 0.5 G = 0.5 10-4 T; B, l and v are mutually perpendicular.

= Bvl = 0.5 10-4 20 10 20

= 2 10-2 10 V = 20 10 mV

Answer: (3)

JEE Main 2026 (Online) 23rd January Morning Shift

Keep practising — Electromagnetic Induction

2

A simple pendulum made of mass 10 g and a metallic wire of length 10 cm is suspended vertically in a uniform magnetic field of 2 T. The magnetic field direction is perpendicular to the plane of oscillations of the pendulum. If the pendulum is released from an angle of 60 with vertical, then maximum induced EMF between the point of suspension and point of oscillation is mV. (Take g = 10 m/s2)

JEE Main 2026 (Online) 23rd January Morning Shift
3

A circular loop of radius 7 cm is placed in uniform magnetic field of 0.2 T directed perpendicular to plane of loop. The loop is converted into a square loop in 0.5 s . The EMF induced in the loop is mV.

  1. 13.2
  2. 6.6
  3. 1.32
  4. 8.25
JEE Main 2026 (Online) 23rd January Evening Shift
4

Suppose a long solenoid of 100 cm length, radius 2 cm having 500 turns per unit length, carries a current I = 10 ( t) A, where = 1000 rad/s. A circular conducting loop (B) of radius 1 cm coaxially slid through the solenoid at a speed v = 1 cm/s. The r.m.s. current through the loop when the coil B is inserted 10 cm inside the solenoid is 2 . The value of is . [Resistance of the loop = 10 ]

  1. 80
  2. 280
  3. 100
  4. 197
JEE Main 2026 (Online) 23rd January Evening Shift
5

XPQY is a vertical smooth long loop having a total resistance R where PX is parallel to QY and separation between them is l. A constant magnetic field B perpendicular to the plane of the loop exists in the entire space. A rod CD of length L(L > l) and mass m is made to slide down from rest under the gravity as shown in figure. The terminal speed acquired by the rod is m/s. (g = acceleration due to gravity) [figure]

  1. mgRB2l2
  2. 2mgRB2L2
  3. 2mgRB2l2
  4. 8mgRB2l2
JEE Main 2026 (Online) 22nd January Morning Shift
6

Three identical coils C1, C2 and C3 are closely placed such that they share a common axis. C2 is exactly midway. C1 carries current I in anti-clockwise direction while C3 carries current I in clockwise direction. An induced current flows through C2 will be in clockwise direction when

  1. C1 and C3 move with equal speeds away from C2
  2. C1 moves towards C2 and C3 moves away from C2
  3. C1 and C3 move with equal speeds towards C2
  4. C1 moves away from C2 and C3 moves towards C2
JEE Main 2026 (Online) 22nd January Morning Shift
7

Inductance of a coil with 104 turns per metre is 10 mH and it is connected to a dc source of 10 V with internal resistance of 10 . The energy density in the inductor when the current reaches ( 1e ) of its maximum value is 1e2 J/m3. The value of is . ( 0 = 4 10-7 T m/A).

JEE Main 2026 (Online) 22nd January Morning Shift
8

Figure shows the circuit that contains three resistances (9 each) and two inductors (4 mH each). The reading of ammeter at the moment switch K is turned ON, is A. [figure]

  1. 2
  2. 3
  3. 1
  4. zero
JEE Main 2026 (Online) 22nd January Evening Shift
9

A conducting circular loop is rotated about its diameter at a constant angular speed of 100 rad/s in a magnetic field of 0.5 T perpendicular to the axis of rotation. When the loop is rotated by 30 from the horizontal position, the induced EMF is 15.4 mV. The radius of the loop is mm. (Take = 227)

JEE Main 2026 (Online) 22nd January Evening Shift
10

A conducting circular loop of area 1.0 m2 is placed perpendicular to a magnetic field which varies as B = (100t) Tesla. If the resistance of the loop is 100 , then the average thermal energy dissipated in the loop in one period is J.

  1. 2
  2. 2
  3. 2
JEE Main 2026 (Online) 21st January Morning Shift
11

A 1 m long metal rod AB completes the circuit as shown in figure. The area of circuit is perpendicular to the magnetic field of 0.10 T. If the resistance of the total circuit is 2 then the force needed to move the rod towards right with constant speed (v) of 1.5 m/s is N. [figure]

  1. 5.7 10-2
  2. 7.5 10-3
  3. 5.7 10-3
  4. 7.5 10-2
JEE Main 2026 (Online) 21st January Morning Shift

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