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d- and f-Block Elements

JEE Main 2024 (Online) 30th January Evening ShiftMCQEasy📈 Topic in 19% papers+4−1
Ques. 1JEE Main 2024, 30 January (Evening Shift)

Alkaline oxidative fusion of MnO2 gives "A" which on electrolytic oxidation in alkaline solution produces B. A and B respectively are

  1. Mn2O3 and MnO42-
  2. Mn2O7 and MnO4-
  3. MnO42- and MnO4-
  4. MnO42- and Mn2O7

Answer

(3) MnO42- and MnO4-

Solution

Fusion: 2MnO2 + 4KOH + O2 2K2MnO4 + 2H2O ⇒ A = MnO42- (green manganate, Mn +6)

Electrolytic oxidation (alkaline, at anode): MnO42- MnO4- + e- ⇒ B = MnO4- (purple permanganate, Mn +7)

∵ this is the commercial preparation of KMnO4

Answer: (3)

Keep practising — d- and f-Block Elements

Ques. 2JEE Main 2024, 30 January (Evening Shift)

The orange colour of K2Cr2O7 and purple colour of KMnO4 is due to

  1. Charge transfer transition in both.
  2. d d transitions in KMnO4 and charge transfer transitions in K2Cr2O7.
  3. d d transitions in both
  4. d d transitions in K2Cr2O7 and charge transfer transitions in KMnO4.
Ques. 3JEE Main 2024, 29 January (Morning Shift)

KMnO4 decomposes on heating at 513 K to form O2 along with

  1. K2MnO4 & Mn
  2. MnO2 & K2O2
  3. K2MnO4 & MnO2
  4. Mn & KO2
Ques. 4JEE Main 2024, 29 January (Morning Shift)

In alkaline medium, MnO4- oxidises I- to

  1. I2
  2. IO3-
  3. IO-
  4. IO4-
Ques. 5JEE Main 2024, 29 January (Evening Shift)

Which of the following acts as a strong reducing agent? (Atomic number: Ce = 58, Eu = 63, Gd = 64, Lu = 71)

  1. Eu2+
  2. Gd3+
  3. Lu3+
  4. Ce4+
Ques. 6JEE Main 2024, 29 January (Evening Shift)

Which of the following statements are correct about Zn, Cd and Hg? Choose the most appropriate from the options given below:

  1. C, D only
  2. B, C only
  3. A, D only
  4. B, D only
Ques. 7JEE Main 2024, 27 January (Morning Shift)

Which of the following electronic configuration would be associated with the highest magnetic moment?

  1. [Ar]3d7
  2. [Ar]3d8
  3. [Ar]3d3
  4. [Ar]3d6
Ques. 8JEE Main 2024, 27 January (Morning Shift)

The electronic configuration for Neodymium is: [Atomic Number for Neodymium 60]

  1. [Xe]4f4 6s2
  2. [Xe]5f4 7s2
  3. [Xe]4f6 6s2
  4. [Xe]4f1 5d1 6s2
Ques. 9JEE Main 2024, 27 January (Evening Shift)

Identify the incorrect pair from the following :

  1. Haber process - Iron
  2. Polythene preparation - TiCl4, Al(CH3)3
  3. Photography - AgBr
  4. Wacker process - PtCl2
Ques. 10JEE Main 2024, 27 January (Evening Shift)

Given below are two statements : In the light of the above statements, choose the most appropriate answer from the options given below :

  1. Both Statement I and Statement II are false
  2. Statement I is true but Statement II is false
  3. Both Statement I and Statement II are true
  4. Statement I is false but Statement II is true
Ques. 11JEE Main 2024, 27 January (Evening Shift)

Choose the correct option having all the elements with d10 electronic configuration from the following :

  1. 46Pd, 28Ni, 26Fe, 24Cr
  2. 29Cu, 30Zn, 48Cd, 47Ag
  3. 27Co, 28Ni, 26Fe, 24Cr
  4. 28Ni, 24Cr, 26Fe, 29Cu

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