The acceptor level of a p-type semiconductor is 6 eV. The maximum wavelength of light which can create a hole would be : Given hc = 1242 eV nm.
- 407 nm
- 103.5 nm
- 414 nm
- 207 nm
Answer
(4) 207 nm
Solution
To create a hole, the photon must lift an electron to the acceptor level:
E = hc 6 eV
= hcE = 12426 nm
= 207 nm
Answer: (4)