PYQSide ExamsMy practice

Molecular Basis of Inheritance · Question 136

AIPMT 2005MCQEasy📈 Topic in 25% papers+4−1
1

Production of a human protein in bacteria by genetic engineering is possible because

  1. The human chromosome can replicate in bacterial cell
  2. The genetic code is universal
  3. Bacterial cell can carry out the RNA splicing reactions
  4. The mechanism of gene regulation is identical in humans and bacteria

Answer

(2) The genetic code is universal

Solution

As per NCERT, the genetic code is nearly universal: from bacteria to human, UUU codes for phenylalanine.

⇒ Hence a human gene inserted into a bacterium is translated by the bacterial machinery into the same sequence of amino acids, i.e. the same human protein.

⇒ A human chromosome cannot replicate in a bacterial cell, bacteria cannot splice RNA (their genes have no introns), and gene regulation differs in prokaryotes and eukaryotes.

∴ It is possible because the genetic code is universal.

Answer: (2)

AIPMT 2005

Keep practising — Molecular Basis of Inheritance

2

During replication of a bacterial chromosome DNA synthesis starts from a replication origin site and

  1. RNA primers are involved
  2. is facilitated by telomerase
  3. moves in one direction of the site
  4. moves in bi-directional way
AIPMT 2004
3

Which form of RNA has a structure resembling clover leaf ?

  1. r-RNA
  2. m-RNA
  3. t-RNA
  4. hn-RNA
AIPMT 2004
4

During transcription, if the nucleotide sequence of the DNA strand that is being coded is ATACG, then the nucleotide sequence in the mRNA would be -

  1. UAUGC
  2. TCTGG
  3. UATGC
  4. TATGC
AIPMT 2004
5

The following ratio is generally constant for a given species :-

  1. A+CT+G
  2. G+CA+T
  3. A+GC+T
  4. T+CG+A
AIPMT 2004
6

DNA fingerprinting refers to :-

  1. Techniques used for molecular analysis of different specimens of DNA
  2. Analysis of DNA samples using imprinting devices
  3. Molecular analysis of profiles of DNA samples
  4. Techniques used for identification of fingerprints of individuals
AIPMT 2004
7

The telomeres of eukaryotic chromosomes consist of short sequences of

  1. Adenine rich repeats
  2. Cytosine rich repeats
  3. Thymine rich repeats
  4. Guanine rich repeats
AIPMT 2004
8

What would happen if in a gene encoding a polypeptide of 50 amino acids, 25th codon (UAU) is mutated to UAA?

  1. A polypeptide of 49 amino acids will be formed
  2. A polypeptide of 25 amino acids will be formed
  3. Two polypeptides of 24 and 25 amino acids will be formed
  4. A polypeptide of 24 amino acids will be formed
AIPMT 2003
9

What does "lac" refer to in what we call the lac operon?

  1. The number 1,00,000
  2. Lac insect
  3. Lactase
  4. Lactose
AIPMT 2003
10

During translation initiation in prokaryotes, a GTP molecule is needed in:

  1. Association of 30S-mRNA with formyl-met-tRNA
  2. Formation of formyl-met-tRNA
  3. Association of 50S subunit of ribosome with initiation complex
  4. Binding of 30S subunit of ribosome with mRNA
AIPMT 2003
11

Which one of the following triplet codes, is correctly matched with its specificity for an amino acid in protein synthesis or as 'start' or 'stop' codon?

  1. UUU – Stop
  2. UAC – Tyrosine
  3. UGU – Leucine
  4. UCG – Start
AIPMT 2003

All Molecular Basis of Inheritance PYQs →

PDFDownload Molecular Basis of Inheritance PYQs as PDF Free, with answer key and a QR code to every solution — print it or study offline⬇
All NEET Botany chapters
Class 11The Living WorldBiological ClassificationPlant KingdomMorphology of Flowering PlantsAnatomy of Flowering PlantsCell: The Unit of LifeCell Cycle and Cell DivisionTransport in PlantsMineral NutritionPhotosynthesis in Higher PlantsRespiration in PlantsPlant Growth and Development
Class 12Reproduction in OrganismsSexual Reproduction in Flowering PlantsPrinciples of Inheritance and VariationMolecular Basis of InheritanceStrategies for Enhancement in Food ProductionMicrobes in Human WelfareOrganisms and PopulationsEcosystemBiodiversity and ConservationEnvironmental Issues
Other chaptersBiomolecules (Biology)