An ac current is represented as i = 5 2 + 10 (650 t + 6 ) Amp The r.m.s. value of the current is
- 10 Amp
- 5 2 Amp
- 100 Amp
- 50 Amp
Answer
(1) 10 Amp
Solution
i = I1 + I0 ( t + ) with I1 = 5 2 A (dc part), I0 = 10 A
irms2 = i2 = I12 + 2I1 I0 ( t + ) + I02 2( t + )
( t + ) = 0 and 2( t + ) = 12
irms2 = 50 + 1002 = 100
irms = 10 A
Answer: (1)