PYQSide ExamsMy practice

System of Particles and Rotational Motion · Question 37

JEE Main 2025 (Online) 4th April Morning ShiftMCQEasy📈 Topic in 16% papers+4−1
1

Which of the following are correct expressions for torque acting on a body? ( r = position vector; p = linear momentum; L = angular momentum; = angular acceleration; I = moment of inertia; F = force; t = time) Choose the correct answer from the options given below:

  1. A, B, D and E Only
  2. C and D Only
  3. B, C, D and E Only
  4. B, D and E Only

Answer

(3) B, C, D and E Only

Solution

E: Torque is the moment of force about the origin: = r F E is correct.

C: By Newton's second law, F = d pdt = r d pdt C is correct.

B: ddt( r p) = d rdt p + r d pdt

= v m v + r F = 0 + r F

= d Ldt B is correct.

D: For a rigid body rotating about a fixed axis, = I (rotational analogue of F = ma) D is correct.

A: r L has dimensions [L] [ML2T-1] = [ML3T-1], whereas torque has [ML2T-2] A is incorrect.

B, C, D and E only.

Answer: (3)

JEE Main 2025 (Online) 4th April Morning Shift

Keep practising — System of Particles and Rotational Motion

2

A circular ring and a solid sphere having same radius roll down on an inclined plane from rest without slipping. The ratio of their velocities when reached at the bottom of the plane is x5 where x = .

JEE Main 2025 (Online) 4th April Morning Shift
3

A wheel is rolling on a plane surface. The speed of a particle on the highest point of the rim is 8 m/s. The speed of the particle on the rim of the wheel at the same level as the centre of the wheel, will be :

  1. 4 2 m/s
  2. 8 m/s
  3. 4 m/s
  4. 8 2 m/s
JEE Main 2025 (Online) 4th April Evening Shift
4

A solid sphere with uniform density and radius R is rotating initially with constant angular velocity ( 1) about its diameter. After some time during the rotation it starts losing mass at a uniform rate, with no change in its shape. The angular velocity of the sphere when its radius becomes R/2 is x 1. The value of x is .

JEE Main 2025 (Online) 4th April Evening Shift
5

A force of 49 N acts tangentially at the highest point of a sphere (solid) of mass 20 kg, kept on a rough horizontal plane. If the sphere rolls without slipping, then the acceleration of the center of the sphere is [figure]

  1. 2.5 m/s2
  2. 3.5 m/s2
  3. 0.25 m/s2
  4. 0.35 m/s2
JEE Main 2025 (Online) 3rd April Morning Shift
6

Moment of inertia of a rod of mass 'M' and length 'L' about an axis passing through its center and normal to its length is ' '. Now the rod is cut into two equal parts and these parts are joined symmetrically to form a cross shape. Moment of inertia of cross about an axis passing through its center and normal to plane containing cross is :

  1. /4
  2. /8
  3. /2
JEE Main 2025 (Online) 2nd April Morning Shift
7

A square lamina OABC of length 10 cm is pivoted at 'O'. Forces act at lamina as shown in figure. If lamina remains stationary, then the magnitude of F is : [figure]

  1. 10 N
  2. 0 (zero)
  3. 10 2 N
  4. 20 N
JEE Main 2025 (Online) 2nd April Morning Shift
8

A cord of negligible mass is wound around the rim of a wheel supported by spokes with negligible mass. The mass of wheel is 10 kg and radius is 10 cm and it can freely rotate without any friction. Initially the wheel is at rest. If a steady pull of 20 N is applied on the cord, the angular velocity of the wheel, after the cord is unwound by 1 m, would be: [figure]

  1. 20 rad/s
  2. 30 rad/s
  3. 10 rad/s
  4. 0 rad/s
JEE Main 2025 (Online) 2nd April Morning Shift
9

The moment of inertia of a circular ring of mass M and diameter r about a tangential axis lying in the plane of the ring is :

  1. 38Mr2
  2. 2Mr2
  3. 12Mr2
  4. 32Mr2
JEE Main 2025 (Online) 2nd April Evening Shift
10

[figure] A wheel of radius 0.2 m rotates freely about its center when a string that is wrapped over its rim is pulled by a force of 10 N as shown in figure. The established torque produces an angular acceleration of 2 rad/s2. Moment of inertia of the wheel is kg m2. (Acceleration due to gravity = 10 m/s2)

JEE Main 2025 (Online) 2nd April Evening Shift
11

The coordinates of a particle with respect to origin in a given reference frame is (1, 1, 1) meters. If a force of F = i - j + k acts on the particle, then the magnitude of torque (with respect to origin) in z-direction is .

JEE Main 2025 (Online) 29th January Morning Shift

All System of Particles and Rotational Motion PYQs →

PDFDownload System of Particles and Rotational Motion PYQs as PDF Free, with answer key and a QR code to every solution — print it or study offline⬇
All JEE Main Physics chapters