A circular current loop of radius R is placed inside square loop of side length L (L R) such that they are co-planar and their centers coincide. The permeability of free space is 0. The mutual inductance between circular loop and square loop is .
- 2 2 0 L2R
- 2 0 L2R
- 2 0 R2L
- 2 2 0 R2L
Answer
(4) 2 2 0 R2L
Solution
Pass a current I through the square loop.
Field at the centre due to one side (distance L2, angles 45° each side):
B1 = 0I4 (L/2)( 45° + 45°) = 2 0I2 L
All four sides add: B = 4B1 = 2 2 0I L
∵ L R, B is uniform over the circular loop:
= B R2 = 2 2 0IR2L
M = I = 2 2 0R2L
Answer: (4)