Suppose a long solenoid of 100 cm length, radius 2 cm having 500 turns per unit length, carries a current I = 10 ( t) A, where = 1000 rad/s. A circular conducting loop (B) of radius 1 cm coaxially slid through the solenoid at a speed v = 1 cm/s. The r.m.s. current through the loop when the coil B is inserted 10 cm inside the solenoid is 2 . The value of is . [Resistance of the loop = 10 ]
- 80
- 280
- 100
- 197
Answer
(4) 197
Solution
The loop is 10 cm inside a long solenoid, the field over it is uniform: B = 0 n I (with n = 500 turns m-1). Moving the loop along the axis does not change this field, so only the changing current induces an emf.
Flux through loop B: = 0 n I ( r2), with r = 1 cm = 10-2 m
e = - d dt = - 0 n r2 (10 ) ( t)
e0 = (4 10-7)(500)( 10-4)(10 1000)
= 2 2 10-4 V
1.974 10-3 V
i0 = e0R = 1.974 10-310 = 1.974 10-4 A 197
irms = i0 2 = 197 2 = 197
Answer: (4)