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The internal energy of air in 4 m 4 m 3 m sized room at 1 atmospheric pressure will be 106 J (Consider air as diatomic molecule)
12
Diatomic gas: f = 5 U = f2nRT = 52PV
V = 4 4 3 = 48 m3, P = 1 atm = 1.013 105 Pa
U = 52 1.013 105 48
= 1.216 107 J 12 106 J
Answer: 12
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