Which of the following is correct set of 4 quantum numbers of 19th electron in Chromium (Atomic number = 24) in accordance with Aufbau principle?
- n = 3, l = 2, m = +2, s = + 12
- n = 3, l = 2, m = -2, s = + 12
- n = 4, l = 1, m = 0, s = + 12
- n = 4, l = 0, m = 0, s = + 12
Answer
(4) n = 4, l = 0, m = 0, s = + 12
Solution
Aufbau order: 1s < 2s < 2p < 3s < 3p < 4s < 3d …
1s2 2s2 2p6 3s2 3p6 accommodates 18 electrons.
∴ The 19th electron enters the 4s orbital (4s has n + l = 4, lower than 3d with n + l = 5).
For a 4s electron: n = 4, l = 0, m = 0 and s = + 12 (first electron in the orbital).
Answer: (4)