The wavelength of photon 'A' is 400 nm. The frequency of photon 'B' is 1016 s-1. The wave number of photon 'C' is 104 cm-1. The correct order of energy of these photons is :
- A > C > B
- C > B > A
- B > A > C
- A > B > C
Answer
(3) B > A > C
Solution
E = h , so compare frequencies.
A: = c = 3 108400 10-9 = 7.5 1014 s-1
B: = 1016 s-1
C: = c = (3 1010 cm s-1)(104 cm-1) = 3 1014 s-1
B > A > C
Energy: B > A > C
Answer: (3)