A particle of mass m oscillates with simple harmonic motion between points x1 and x2, the equilibrium position being O. Its potential energy is plotted. It will be as given below in the graph
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Answer
(1) [figure]
Solution
As per NCERT, potential energy in SHM is U = 12kx2, x being the displacement from O.
⇒ U is zero at the equilibrium position O and increases as x2 on both sides.
⇒ U is maximum at the end points x1 and x2.
∴ The graph is a parabola opening upwards with its minimum at O.
Answer: (1)