An organic compound has 42.1\% carbon, 6.4\% hydrogen and the remainder is oxygen. If its molecular weight is 342, then its molecular formula is :
- C14H20O10
- C12H22O11
- C12H20O12
- C11H18O12
Answer
(2) C12H22O11
Solution
O = 100 - 42.1 - 6.4 = 51.5\%
Atoms of an element in one molecule:
n = \% M100 atomic mass
C = 42.1 342100 12 = 12.0
H = 6.4 342100 1 = 21.9 22
O = 51.5 342100 16 = 11.0
⇒ C12H22O11 (M = 144 + 22 + 176 = 342)
Answer: (2)