The Molarity (M) of an aqueous solution containing 5.85 g of NaCl in 500 mL water is : (Given : Molar Mass Na : 23 and Cl : 35.5 g mol-1)
- 20
- 4
- 2
- 0.2
Answer
(4) 0.2
Solution
M = nsoluteVsolution (L) (solution volume taken as 500 mL)
Molar mass of NaCl = 23 + 35.5 = 58.5 g mol-1
⇒ n = 5.8558.5 = 0.1 mol
⇒ M = 0.10.5 = 0.2 M
Answer: (4)