Two gases A and B having the same volume diffuse through a porous partition in 20 and 10 seconds respectively. The molecular mass of A is 49 u. Molecular mass of B will be
- 50.00 u
- 12.25 u
- 6.50 u
- 25.00 u
Answer
(2) 12.25 u
Solution
By Graham's law, for equal volumes diffused, r 1t and r 1 M
tAtB = MAMB
2010 = 49MB
4 = 49MB
MB = 494 = 12.25 u
Answer: (2)