Which of these statements about [Co(CN)6]3- is true?
- [Co(CN)6]3- has four unpaired electrons and will be in a high-spin configuration.
- [Co(CN)6]3- has no unpaired electrons and will be in a high-spin configuration.
- [Co(CN)6]3- has no unpaired electrons and will be in a low-spin configuration.
- [Co(CN)6]3- has four unpaired electrons and will be in a low-spin configuration.
Answer
(3) [Co(CN)6]3- has no unpaired electrons and will be in a low-spin configuration.
Solution
In [Co(CN)6]3-: x + 6(-1) = -3 ⇒ x = +3; Co3+: 3d6
CN- is a strong field ligand ⇒ o > P ⇒ electrons pair up in t2g
⇒ Configuration t2g6 eg0 ⇒ no unpaired electrons, low-spin (inner orbital, d2sp3) complex, diamagnetic.
Answer: (3)