An excess of AgNO3 is added to 100 mL of a 0.01 M solution of dichlorotetraaquachromium(III) chloride. The number of moles of AgCl precipitated would be
- 0.003
- 0.01
- 0.001
- 0.002
Answer
(3) 0.001
Solution
Dichlorotetraaquachromium(III) chloride is [Cr(H2O)4Cl2]Cl.
Only the chloride outside the coordination sphere (ionisable) is precipitated by AgNO3:
[Cr(H2O)4Cl2]Cl + AgNO3 [Cr(H2O)4Cl2]NO3 + AgCl
Moles of complex = 0.01 0.100 = 0.001 mol
∴ Moles of AgCl = 1 0.001 = 0.001
Answer: (3)