If a satellite orbiting the Earth is 9 times closer to the Earth than the Moon, what is the time period of rotation of the satellite? Given rotational time period of Moon = 27 days and gravitational attraction between the satellite and the moon is neglected.
- 3 days
- 27 days
- 81 days
- 1 day
Answer
(4) 1 day
Solution
Both orbit the Earth, so Kepler's third law applies:
T2 r3
[figure]
TsTm= ( 19 )3/2= 127
Ts= 2727=1 day
Answer: (4)