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Gravitation

JEE Main 2025 (Online) 23rd January Evening ShiftMCQEasy📈 Topic in 11% papers+4−1
Ques. 1JEE Main 2025, 23 January (Evening Shift)

If a satellite orbiting the Earth is 9 times closer to the Earth than the Moon, what is the time period of rotation of the satellite? Given rotational time period of Moon = 27 days and gravitational attraction between the satellite and the moon is neglected.

  1. 3 days
  2. 27 days
  3. 81 days
  4. 1 day

Answer

(4) 1 day

Solution

Both orbit the Earth, so Kepler's third law applies:

T2 r3

[figure]

TsTm= ( 19 )3/2= 127

Ts= 2727=1 day

Answer: (4)

Keep practising — Gravitation

Ques. 2JEE Main 2025, 23 January (Evening Shift)

A satellite of mass M2 is revolving around earth in a circular orbit at a height of R3 from earth surface. The angular momentum of the satellite is M GMRx. The value of x is , where M and R are the mass and radius of earth, respectively. ( G is the gravitational constant)

Ques. 3JEE Main 2025, 22 January (Morning Shift)

A small point of mass m is placed at a distance 2R from the centre ' O ' of a big uniform solid sphere of mass M and radius R . The gravitational force on ' m ' due to M is F1. A spherical part of radius R/3 is removed from the big sphere as shown in the figure and the gravitational force on m due to remaining part of M is found to be F2. The value of ratio F1:F2 is [figure]

  1. 11 : 10
  2. 12 : 11
  3. 16 : 9
  4. 12 : 9

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