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Gravitation

JEE Main 2025 (Online) 23rd January Evening ShiftNumericalEasy📈 Topic in 8% papers+4
Ques. 1JEE Main 2025, 23 January (Evening Shift)

A satellite of mass M2 is revolving around earth in a circular orbit at a height of R3 from earth surface. The angular momentum of the satellite is M GMRx. The value of x is , where M and R are the mass and radius of earth, respectively. ( G is the gravitational constant)

Answer

3

Solution

Orbit radius from the Earth's centre: r=R+ R3= 4R3.

[figure]

L=mvr=m GMr= M2 GM 4R3=M GMR3

x=3

Answer: 3

Keep practising — Gravitation

Ques. 2JEE Main 2025, 22 January (Morning Shift)

A small point of mass m is placed at a distance 2R from the centre ' O ' of a big uniform solid sphere of mass M and radius R . The gravitational force on ' m ' due to M is F1. A spherical part of radius R/3 is removed from the big sphere as shown in the figure and the gravitational force on m due to remaining part of M is found to be F2. The value of ratio F1:F2 is [figure]

  1. 11 : 10
  2. 12 : 11
  3. 16 : 9
  4. 12 : 9

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