A small point of mass m is placed at a distance 2R from the centre ' O ' of a big uniform solid sphere of mass M and radius R . The gravitational force on ' m ' due to M is F1. A spherical part of radius R/3 is removed from the big sphere as shown in the figure and the gravitational force on m due to remaining part of M is found to be F2. The value of ratio F1:F2 is [figure]
- 11 : 10
- 12 : 11
- 16 : 9
- 12 : 9
Answer
(2) 12 : 11
Solution
Cavity (radius R3): mass M27, centre 2R3 from O, so 4R3 from m. Remaining sphere = full sphere - cavity sphere.
[figure]
F1= GMm4R2, Fcavity= G(M/27) m(4R/3)2= GMm48R2
F2=F1-Fcavity= 11 GMm48R2
F1:F2=12:11
Answer: (2)