Consider the dissociation of the weak acid HX as given below HX(aq) H+(aq) + X-(aq), Ka = 1.2 10-5 [Ka : dissociation constant] The osmotic pressure of 0.03 M aqueous solution of HX at 300 K is 10-2 bar (nearest integer). [Given : R = 0.083 L bar mol-1 K-1]
Answer
76
Solution
Weak acid: = KaC = 1.2 10-50.03 = 4 10-4 = 0.02
∵ HX gives 2 ions ⇒ i = 1 + = 1.02
= iCRT = 1.02 0.03 0.083 300
= 0.762 bar = 76.2 10-2 bar
Answer: 76