The correct order of decreasing second ionisation enthalpy of Ti(22), V(23), Cr(24) and Mn(25) is
- Mn > Cr > Ti > V
- Ti > V > Cr > Mn
- Cr > Mn > V > Ti
- V > Mn > Cr > Ti
Answer
(3) Cr > Mn > V > Ti
Solution
The second electron is removed from the unipositive ion M+.
Cr+ (3d5): the electron must come from a stable half-filled d subshell highest value.
Mn+ (3d54s1): the 4s electron is removed, but the nuclear charge is high next highest.
V+ and Ti+: value increases with nuclear charge V > Ti.
As per NCERT (Table of ionisation enthalpies of 3d series), iH2 ( kJ mol-1): Cr 1592, Mn 1509, V 1414, Ti 1310.
Cr > Mn > V > Ti
Answer: (3)